I(6i-15)=12(38-2i)

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Solution for I(6i-15)=12(38-2i) equation: 



(6I-15)=12(38-2I)

We move all terms to the left:

(6I-15)-(12(38-2I))=0

We add all the numbers together, and all the variables

(6I-15)-(12(-2I+38))=0

We get rid of parentheses

6I-(12(-2I+38))-15=0



We calculate terms in parentheses: -(12(-2I+38)), so:

12(-2I+38)

We multiply parentheses

-24I+456

Back to the equation:

-(-24I+456)



We get rid of parentheses

6I+24I-456-15=0

We add all the numbers together, and all the variables

30I-471=0

We move all terms containing I to the left, all other terms to the right

30I=471

I=471/30

I=15+7/10

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