I(12)=210(1.08t)

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Solution for I(12)=210(1.08t) equation: 



(12)=210(1.08I)

We move all terms to the left:

(12)-(210(1.08I))=0

We add all the numbers together, and all the variables

-(210(+1.08I))+12=0



We calculate terms in parentheses: -(210(+1.08I)), so:

210(+1.08I)

We multiply parentheses

210I

Back to the equation:

-(210I)



We move all terms containing I to the left, all other terms to the right

-210I=-12

I=-12/-210

I=2/35

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