H=2t2-3t+1.125

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Solution for H=2t2-3t+1.125 equation: 



=2H^2-3H+1.125

We move all terms to the left:

-(2H^2-3H+1.125)=0

We get rid of parentheses

-2H^2+3H-1.125=0

a = -2; b = 3; c = -1.125;
Δ = b2-4ac
Δ = 32-4·(-2)·(-1.125)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$H=\frac{-b}{2a}=\frac{-3}{-4}=3/4$

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