H=13.7t-4.9t2

Solution for H=13.7t-4.9t2 equation:

=13.7H-4.9H^2

We move all terms to the left:

-(13.7H-4.9H^2)=0

We get rid of parentheses

4.9H^2-13.7H=0

a = 4.9; b = -13.7; c = 0;
Δ = b2-4ac
Δ = -13.72-4·4.9·0
Δ = 187.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13.7)-\sqrt{187.69}}{2*4.9}=\frac{13.7-\sqrt{187.69}}{9.8}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13.7)+\sqrt{187.69}}{2*4.9}=\frac{13.7+\sqrt{187.69}}{9.8}
$