H(z)=5/2-2z

Solution for H(z)=5/2-2z equation:

(H)=5/2-2H

We move all terms to the left:

(H)-(5/2-2H)=0


Domain of the equation: 2-2H)!=0

We move all terms containing H to the left, all other terms to the right

-2H)!=-2

H!=-2/1

H!=-2

H∈R


We add all the numbers together, and all the variables

H-(-2H+5/2)=0

We get rid of parentheses

H+2H-5/2=0

We multiply all the terms by the denominator


H*2+2H*2-5=0

Wy multiply elements

2H+4H-5=0

We add all the numbers together, and all the variables

6H-5=0

We move all terms containing H to the left, all other terms to the right

6H=5

H=5/6

H=5/6