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(H)=H2-3H+5
We move all terms to the left:
(H)-(H2-3H+5)=0
We add all the numbers together, and all the variables
-(+H^2-3H+5)+H=0
We get rid of parentheses
-H^2+3H+H-5=0
We add all the numbers together, and all the variables
-1H^2+4H-5=0
a = -1; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·(-1)·(-5)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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