H(x)=x2+3x/4x+27

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Solution for H(x)=x2+3x/4x+27 equation: 



(H)=H2+3H/4H+27

We move all terms to the left:

(H)-(H2+3H/4H+27)=0



Domain of the equation: 4H+27)!=0

H∈R



We add all the numbers together, and all the variables

-(+H^2+3H/4H+27)+H=0

We get rid of parentheses

-H^2-3H/4H+H-27=0

We multiply all the terms by the denominator


-H^2*4H-3H+H*4H-27*4H=0

Wy multiply elements

-4H^3+4H^2-3H-108H=0

We do not support eHpression: H^3

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