H(x)=-2/5x

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Solution for H(x)=-2/5x equation: 



(H)=-2/5H

We move all terms to the left:

(H)-(-2/5H)=0



Domain of the equation: 5H)!=0

H!=0/1

H!=0

H∈R



We get rid of parentheses

H+2/5H=0

We multiply all the terms by the denominator


H*5H+2=0

Wy multiply elements

5H^2+2=0

a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation

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