H(a)=3-2aH(-3)

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Solution for H(a)=3-2aH(-3) equation: 



(H)=3-2H(-3)

We move all terms to the left:

(H)-(3-2H(-3))=0



We calculate terms in parentheses: -(3-2H(-3)), so:

3-2H(-3)

determiningTheFunctionDomain
-2H(-3)+3

We multiply parentheses

6H+3

Back to the equation:

-(6H+3)



We get rid of parentheses

H-6H-3=0

We add all the numbers together, and all the variables

-5H-3=0

We move all terms containing H to the left, all other terms to the right

-5H=3

H=3/-5

H=-3/5

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