H(7c+8)=2(7c+8)

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Solution for H(7c+8)=2(7c+8) equation: 



(7H+8)=2(7H+8)

We move all terms to the left:

(7H+8)-(2(7H+8))=0

We get rid of parentheses

7H-(2(7H+8))+8=0



We calculate terms in parentheses: -(2(7H+8)), so:

2(7H+8)

We multiply parentheses

14H+16

Back to the equation:

-(14H+16)



We get rid of parentheses

7H-14H-16+8=0

We add all the numbers together, and all the variables

-7H-8=0

We move all terms containing H to the left, all other terms to the right

-7H=8

H=8/-7

H=-1+1/7

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