H(26.8)=0.2d2-35

Solution for H(26.8)=0.2d2-35 equation:

(26.8)=0.2H^2-35

We move all terms to the left:

(26.8)-(0.2H^2-35)=0

We add all the numbers together, and all the variables

-(0.2H^2-35)+26.8=0

We get rid of parentheses

-0.2H^2+35+26.8=0

We add all the numbers together, and all the variables

-0.2H^2+61.8=0

a = -0.2; b = 0; c = +61.8;
Δ = b2-4ac
Δ = 02-4·(-0.2)·61.8
Δ = 49.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{49.44}}{2*-0.2}=\frac{0-\sqrt{49.44}}{-0.4}
=-\frac{\sqrt{}}{-0.4}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{49.44}}{2*-0.2}=\frac{0+\sqrt{49.44}}{-0.4}
=\frac{\sqrt{}}{-0.4}
$