H(14)=2x+3+5(x-7)

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Solution for H(14)=2x+3+5(x-7) equation: 



(14)=2H+3+5(H-7)

We move all terms to the left:

(14)-(2H+3+5(H-7))=0



We calculate terms in parentheses: -(2H+3+5(H-7)), so:

2H+3+5(H-7)

determiningTheFunctionDomain
2H+5(H-7)+3

We multiply parentheses

2H+5H-35+3

We add all the numbers together, and all the variables

7H-32

Back to the equation:

-(7H-32)



We get rid of parentheses

-7H+32+14=0

We add all the numbers together, and all the variables

-7H+46=0

We move all terms containing H to the left, all other terms to the right

-7H=-46

H=-46/-7

H=6+4/7

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