G4(3x+2)=68

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Solution for G4(3x+2)=68 equation: 



4(3G+2)=68

We move all terms to the left:

4(3G+2)-(68)=0

We multiply parentheses

12G+8-68=0

We add all the numbers together, and all the variables

12G-60=0

We move all terms containing G to the left, all other terms to the right

12G=60

G=60/12

G=5

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