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(G)=G2-6G-16
We move all terms to the left:
(G)-(G2-6G-16)=0
We add all the numbers together, and all the variables
-(+G^2-6G-16)+G=0
We get rid of parentheses
-G^2+6G+G+16=0
We add all the numbers together, and all the variables
-1G^2+7G+16=0
a = -1; b = 7; c = +16;
Δ = b2-4ac
Δ = 72-4·(-1)·16
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{113}}{2*-1}=\frac{-7-\sqrt{113}}{-2} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{113}}{2*-1}=\frac{-7+\sqrt{113}}{-2} $
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