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(G)=G2+11G
We move all terms to the left:
(G)-(G2+11G)=0
We add all the numbers together, and all the variables
-(+G^2+11G)+G=0
We get rid of parentheses
-G^2-11G+G=0
We add all the numbers together, and all the variables
-1G^2-10G=0
a = -1; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-1}=\frac{0}{-2} =0 $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-1}=\frac{20}{-2} =-10 $
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