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(G)=-0.01G^2+G+68

We move all terms to the left:

(G)-(-0.01G^2+G+68)=0

We get rid of parentheses

0.01G^2-G+G-68=0

We add all the numbers together, and all the variables

0.01G^2-68=0

a = 0.01; b = 0; c = -68;

Δ = b^{2}-4ac

Δ = 0^{2}-4·0.01·(-68)

Δ = 2.72

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.72}}{2*0.01}=\frac{0-\sqrt{2.72}}{0.02} =-\frac{\sqrt{}}{0.02} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.72}}{2*0.01}=\frac{0+\sqrt{2.72}}{0.02} =\frac{\sqrt{}}{0.02} $

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