# G(x)=-0.01x^2+x+68

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## Solution for G(x)=-0.01x^2+x+68 equation:

(G)=-0.01G^2+G+68
We move all terms to the left:
(G)-(-0.01G^2+G+68)=0
We get rid of parentheses
0.01G^2-G+G-68=0
We add all the numbers together, and all the variables
0.01G^2-68=0
a = 0.01; b = 0; c = -68;Δ = b2-4acΔ = 02-4·0.01·(-68)Δ = 2.72The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.72}}{2*0.01}=\frac{0-\sqrt{2.72}}{0.02} =-\frac{\sqrt{}}{0.02}$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.72}}{2*0.01}=\frac{0+\sqrt{2.72}}{0.02} =\frac{\sqrt{}}{0.02}$

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