G(-12)=3/4x+10

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Solution for G(-12)=3/4x+10 equation: 



(-12)=3/4G+10

We move all terms to the left:

(-12)-(3/4G+10)=0



Domain of the equation: 4G+10)!=0

G∈R



We add all the numbers together, and all the variables

-(3/4G+10)-12=0

We get rid of parentheses

-3/4G-10-12=0

We multiply all the terms by the denominator


-10*4G-12*4G-3=0

Wy multiply elements

-40G-48G-3=0

We add all the numbers together, and all the variables

-88G-3=0

We move all terms containing G to the left, all other terms to the right

-88G=3

G=3/-88

G=-3/88

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