F=9/5c=10+32

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Solution for F=9/5c=10+32 equation: 



=9/5F=10+32

We move all terms to the left:

-(9/5F)=0



Domain of the equation: 5F)!=0

F!=0/1

F!=0

F∈R



We add all the numbers together, and all the variables

-(+9/5F)=0

We get rid of parentheses

-9/5F=0

We multiply all the terms by the denominator


-9!=0

There is no solution for this equation

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