F=9/5(c-5)+32

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Solution for F=9/5(c-5)+32 equation: 



=9/5(F-5)+32

We move all terms to the left:

-(9/5(F-5)+32)=0



Domain of the equation: 5(F-5)+32)!=0

F∈R



We multiply all the terms by the denominator


-(9=0

We add all the numbers together, and all the variables

=0

F=0/1

F=0

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