F=7/5(n-53)

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Solution for F=7/5(n-53) equation: 



=7/5(F-53)

We move all terms to the left:

-(7/5(F-53))=0



Domain of the equation: 5(F-53))!=0

F∈R



We multiply all the terms by the denominator


-(7=0

We add all the numbers together, and all the variables

=0

F=0/1

F=0

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