F=10/2x-2x

Solution for F=10/2x-2x equation:

=10/2F-2F

We move all terms to the left:

-(10/2F-2F)=0


Domain of the equation: 2F-2F)!=0

F∈R


We add all the numbers together, and all the variables

-(-2F+10/2F)=0

We get rid of parentheses

2F-10/2F=0

We multiply all the terms by the denominator


2F*2F-10=0

Wy multiply elements

4F^2-10=0

a = 4; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·4·(-10)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*4}=\frac{0-4\sqrt{10}}{8}
=-\frac{4\sqrt{10}}{8}
=-\frac{\sqrt{10}}{2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*4}=\frac{0+4\sqrt{10}}{8}
=\frac{4\sqrt{10}}{8}
=\frac{\sqrt{10}}{2}
$