F=(9/5)x25+32

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Solution for F=(9/5)x25+32 equation: 



=(9/5)F25+32

We move all terms to the left:

-((9/5)F25+32)=0



Domain of the equation: 5)F25+32)!=0

F!=0/1

F!=0

F∈R



We add all the numbers together, and all the variables

-((+9/5)F25+32)=0

We multiply all the terms by the denominator


-((+9=0

We add all the numbers together, and all the variables

=0

F=0/1

F=0

Równanie nie ma rozwiązania

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