F(x)=x2-5x+12

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Solution for F(x)=x2-5x+12 equation: 



(F)=F2-5F+12

We move all terms to the left:

(F)-(F2-5F+12)=0

We add all the numbers together, and all the variables

-(+F^2-5F+12)+F=0

We get rid of parentheses

-F^2+5F+F-12=0

We add all the numbers together, and all the variables

-1F^2+6F-12=0

a = -1; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·(-1)·(-12)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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