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(F)=F2-3F+6
We move all terms to the left:
(F)-(F2-3F+6)=0
We add all the numbers together, and all the variables
-(+F^2-3F+6)+F=0
We get rid of parentheses
-F^2+3F+F-6=0
We add all the numbers together, and all the variables
-1F^2+4F-6=0
a = -1; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation
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