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(F)=F2-2F-3
We move all terms to the left:
(F)-(F2-2F-3)=0
We add all the numbers together, and all the variables
-(+F^2-2F-3)+F=0
We get rid of parentheses
-F^2+2F+F+3=0
We add all the numbers together, and all the variables
-1F^2+3F+3=0
a = -1; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·(-1)·3
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{21}}{2*-1}=\frac{-3-\sqrt{21}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{21}}{2*-1}=\frac{-3+\sqrt{21}}{-2} $
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