F(x)=x2-14x+44

Solution for F(x)=x2-14x+44 equation:

(F)=F2-14F+44

We move all terms to the left:

(F)-(F2-14F+44)=0

We add all the numbers together, and all the variables

-(+F^2-14F+44)+F=0

We get rid of parentheses

-F^2+14F+F-44=0

We add all the numbers together, and all the variables

-1F^2+15F-44=0

a = -1; b = 15; c = -44;
Δ = b2-4ac
Δ = 152-4·(-1)·(-44)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-7}{2*-1}=\frac{-22}{-2}
=+11
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+7}{2*-1}=\frac{-8}{-2}
=+4
$