F(x)=x2-10x+39

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Solution for F(x)=x2-10x+39 equation: 



(F)=F2-10F+39

We move all terms to the left:

(F)-(F2-10F+39)=0

We add all the numbers together, and all the variables

-(+F^2-10F+39)+F=0

We get rid of parentheses

-F^2+10F+F-39=0

We add all the numbers together, and all the variables

-1F^2+11F-39=0

a = -1; b = 11; c = -39;
Δ = b2-4ac
Δ = 112-4·(-1)·(-39)
Δ = -35
Delta is less than zero, so there is no solution for the equation

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