F(x)=x2+3x+8

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Solution for F(x)=x2+3x+8 equation: 



(F)=F2+3F+8

We move all terms to the left:

(F)-(F2+3F+8)=0

We add all the numbers together, and all the variables

-(+F^2+3F+8)+F=0

We get rid of parentheses

-F^2-3F+F-8=0

We add all the numbers together, and all the variables

-1F^2-2F-8=0

a = -1; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·(-1)·(-8)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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