F(x)=x2+-6

Solution for F(x)=x2+-6 equation:

(F)=F2+-6

We move all terms to the left:

(F)-(F2+-6)=0

We add all the numbers together, and all the variables

-(+F^2+-6)+F=0

We use the square of the difference formula

-(+F^2-6)+F=0

We get rid of parentheses

-F^2+F+6=0

We add all the numbers together, and all the variables

-1F^2+F+6=0

a = -1; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-1)·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5}{2*-1}=\frac{-6}{-2}
=+3
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5}{2*-1}=\frac{4}{-2}
=-2
$