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(F)=7/3F-3
We move all terms to the left:
(F)-(7/3F-3)=0
Domain of the equation: 3F-3)!=0We get rid of parentheses
F∈R
F-7/3F+3=0
We multiply all the terms by the denominator
F*3F+3*3F-7=0
Wy multiply elements
3F^2+9F-7=0
a = 3; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·3·(-7)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{165}}{2*3}=\frac{-9-\sqrt{165}}{6} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{165}}{2*3}=\frac{-9+\sqrt{165}}{6} $
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