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(F)=5F^2+6F+12
We move all terms to the left:
(F)-(5F^2+6F+12)=0
We get rid of parentheses
-5F^2+F-6F-12=0
We add all the numbers together, and all the variables
-5F^2-5F-12=0
a = -5; b = -5; c = -12;
Δ = b2-4ac
Δ = -52-4·(-5)·(-12)
Δ = -215
Delta is less than zero, so there is no solution for the equation
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