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(F)=5/8F
We move all terms to the left:
(F)-(5/8F)=0
Domain of the equation: 8F)!=0We add all the numbers together, and all the variables
F!=0/1
F!=0
F∈R
F-(+5/8F)=0
We get rid of parentheses
F-5/8F=0
We multiply all the terms by the denominator
F*8F-5=0
Wy multiply elements
8F^2-5=0
a = 8; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·8·(-5)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*8}=\frac{0-4\sqrt{10}}{16} =-\frac{4\sqrt{10}}{16} =-\frac{\sqrt{10}}{4} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*8}=\frac{0+4\sqrt{10}}{16} =\frac{4\sqrt{10}}{16} =\frac{\sqrt{10}}{4} $
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