F(x)=4x2+3x+13

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Solution for F(x)=4x2+3x+13 equation: 



(F)=4F^2+3F+13

We move all terms to the left:

(F)-(4F^2+3F+13)=0

We get rid of parentheses

-4F^2+F-3F-13=0

We add all the numbers together, and all the variables

-4F^2-2F-13=0

a = -4; b = -2; c = -13;
Δ = b2-4ac
Δ = -22-4·(-4)·(-13)
Δ = -204
Delta is less than zero, so there is no solution for the equation

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