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(F)=4F/2F
We move all terms to the left:
(F)-(4F/2F)=0
Domain of the equation: 2F)!=0We add all the numbers together, and all the variables
F!=0/1
F!=0
F∈R
F-(+4F/2F)=0
We get rid of parentheses
F-4F/2F=0
We multiply all the terms by the denominator
F*2F-4F=0
We add all the numbers together, and all the variables
-4F+F*2F=0
Wy multiply elements
2F^2-4F=0
a = 2; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·2·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*2}=\frac{0}{4} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*2}=\frac{8}{4} =2 $
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