F(x)=3x2+24x+48

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Solution for F(x)=3x2+24x+48 equation: 



(F)=3F^2+24F+48

We move all terms to the left:

(F)-(3F^2+24F+48)=0

We get rid of parentheses

-3F^2+F-24F-48=0

We add all the numbers together, and all the variables

-3F^2-23F-48=0

a = -3; b = -23; c = -48;
Δ = b2-4ac
Δ = -232-4·(-3)·(-48)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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