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(F)=3F^2+1.(F)=2F-3.(F)=F-1(F)=
We move all terms to the left:
(F)-(3F^2+1.(F))=0
We get rid of parentheses
-3F^2+F-1.F=0
We add all the numbers together, and all the variables
-3F^2=0
a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$F=\frac{-b}{2a}=\frac{0}{-6}=0$
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