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(F)=3/F-14
We move all terms to the left:
(F)-(3/F-14)=0
Domain of the equation: F-14)!=0We get rid of parentheses
F∈R
F-3/F+14=0
We multiply all the terms by the denominator
F*F+14*F-3=0
We add all the numbers together, and all the variables
14F+F*F-3=0
Wy multiply elements
F^2+14F-3=0
a = 1; b = 14; c = -3;
Δ = b2-4ac
Δ = 142-4·1·(-3)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4\sqrt{13}}{2*1}=\frac{-14-4\sqrt{13}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4\sqrt{13}}{2*1}=\frac{-14+4\sqrt{13}}{2} $
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