F(x)=2x2-3x+2

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Solution for F(x)=2x2-3x+2 equation: 



(F)=2F^2-3F+2

We move all terms to the left:

(F)-(2F^2-3F+2)=0

We get rid of parentheses

-2F^2+F+3F-2=0

We add all the numbers together, and all the variables

-2F^2+4F-2=0

a = -2; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{-4}{-4}=1$

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