F(x)=2x/4x+7

Solution for F(x)=2x/4x+7 equation:

(F)=2F/4F+7

We move all terms to the left:

(F)-(2F/4F+7)=0


Domain of the equation: 4F+7)!=0

F∈R


We get rid of parentheses

F-2F/4F-7=0

We multiply all the terms by the denominator


F*4F-2F-7*4F=0

We add all the numbers together, and all the variables

-2F+F*4F-7*4F=0

Wy multiply elements

4F^2-2F-28F=0

We add all the numbers together, and all the variables

4F^2-30F=0

a = 4; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·4·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*4}=\frac{0}{8}
=0
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*4}=\frac{60}{8}
=7+1/2
$