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(F)=2F+3/4F+5.F=-5/4
We move all terms to the left:
(F)-(2F+3/4F+5.F)=0
Domain of the equation: 4F+5.F)!=0We add all the numbers together, and all the variables
F∈R
F-(+7F+3/4F)=0
We get rid of parentheses
F-7F-3/4F=0
We multiply all the terms by the denominator
F*4F-7F*4F-3=0
Wy multiply elements
4F^2-28F^2-3=0
We add all the numbers together, and all the variables
-24F^2-3=0
a = -24; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-24)·(-3)
Δ = -288
Delta is less than zero, so there is no solution for the equation
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