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(F)=20(4/5)F
We move all terms to the left:
(F)-(20(4/5)F)=0
Domain of the equation: 5)F)!=0We add all the numbers together, and all the variables
F!=0/1
F!=0
F∈R
F-(20(+4/5)F)=0
We multiply all the terms by the denominator
F*5)F)-(20(+4=0
Wy multiply elements
5F^2+4=0
a = 5; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·5·4
Δ = -80
Delta is less than zero, so there is no solution for the equation
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