F(x)=1x2-2x+4

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Solution for F(x)=1x2-2x+4 equation: 



(F)=1F^2-2F+4

We move all terms to the left:

(F)-(1F^2-2F+4)=0

We get rid of parentheses

-1F^2+F+2F-4=0

We add all the numbers together, and all the variables

-1F^2+3F-4=0

a = -1; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-1)·(-4)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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