F(x)=12/4x+2

Solution for F(x)=12/4x+2 equation:

(F)=12/4F+2

We move all terms to the left:

(F)-(12/4F+2)=0


Domain of the equation: 4F+2)!=0

F∈R


We get rid of parentheses

F-12/4F-2=0

We multiply all the terms by the denominator


F*4F-2*4F-12=0

Wy multiply elements

4F^2-8F-12=0

a = 4; b = -8; c = -12;
Δ = b2-4ac
Δ = -82-4·4·(-12)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16}{2*4}=\frac{-8}{8}
=-1
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16}{2*4}=\frac{24}{8}
=3
$