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(F)=1-7F/6F+5
We move all terms to the left:
(F)-(1-7F/6F+5)=0
Domain of the equation: 6F+5)!=0We add all the numbers together, and all the variables
F∈R
F-(-7F/6F+6)=0
We get rid of parentheses
F+7F/6F-6=0
We multiply all the terms by the denominator
F*6F+7F-6*6F=0
We add all the numbers together, and all the variables
7F+F*6F-6*6F=0
Wy multiply elements
6F^2+7F-36F=0
We add all the numbers together, and all the variables
6F^2-29F=0
a = 6; b = -29; c = 0;
Δ = b2-4ac
Δ = -292-4·6·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-29}{2*6}=\frac{0}{12} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+29}{2*6}=\frac{58}{12} =4+5/6 $
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