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(F)=-F2-10F-2
We move all terms to the left:
(F)-(-F2-10F-2)=0
We add all the numbers together, and all the variables
-(-1F^2-10F-2)+F=0
We get rid of parentheses
1F^2+10F+F+2=0
We add all the numbers together, and all the variables
F^2+11F+2=0
a = 1; b = 11; c = +2;
Δ = b2-4ac
Δ = 112-4·1·2
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{113}}{2*1}=\frac{-11-\sqrt{113}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{113}}{2*1}=\frac{-11+\sqrt{113}}{2} $
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