F(x)=-x2+3x+50

Solution for F(x)=-x2+3x+50 equation:

(F)=-F2+3F+50

We move all terms to the left:

(F)-(-F2+3F+50)=0

We add all the numbers together, and all the variables

-(-1F^2+3F+50)+F=0

We get rid of parentheses

1F^2-3F+F-50=0

We add all the numbers together, and all the variables

F^2-2F-50=0

a = 1; b = -2; c = -50;
Δ = b2-4ac
Δ = -22-4·1·(-50)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{51}}{2*1}=\frac{2-2\sqrt{51}}{2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{51}}{2*1}=\frac{2+2\sqrt{51}}{2}
$