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(F)=-6/F+9
We move all terms to the left:
(F)-(-6/F+9)=0
Domain of the equation: F+9)!=0We get rid of parentheses
F∈R
F+6/F-9=0
We multiply all the terms by the denominator
F*F-9*F+6=0
We add all the numbers together, and all the variables
-9F+F*F+6=0
Wy multiply elements
F^2-9F+6=0
a = 1; b = -9; c = +6;
Δ = b2-4ac
Δ = -92-4·1·6
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{57}}{2*1}=\frac{9-\sqrt{57}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{57}}{2*1}=\frac{9+\sqrt{57}}{2} $
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