F(x)=-5x(2)+200

Solution for F(x)=-5x(2)+200 equation:

(F)=-5F(2)+200

We move all terms to the left:

(F)-(-5F(2)+200)=0

We add all the numbers together, and all the variables

-(-5F^2+200)+F=0

We get rid of parentheses

5F^2+F-200=0

a = 5; b = 1; c = -200;
Δ = b2-4ac
Δ = 12-4·5·(-200)
Δ = 4001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{4001}}{2*5}=\frac{-1-\sqrt{4001}}{10}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{4001}}{2*5}=\frac{-1+\sqrt{4001}}{10}
$