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(F)=-3/10F-8
We move all terms to the left:
(F)-(-3/10F-8)=0
Domain of the equation: 10F-8)!=0We get rid of parentheses
F∈R
F+3/10F+8=0
We multiply all the terms by the denominator
F*10F+8*10F+3=0
Wy multiply elements
10F^2+80F+3=0
a = 10; b = 80; c = +3;
Δ = b2-4ac
Δ = 802-4·10·3
Δ = 6280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6280}=\sqrt{4*1570}=\sqrt{4}*\sqrt{1570}=2\sqrt{1570}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-2\sqrt{1570}}{2*10}=\frac{-80-2\sqrt{1570}}{20} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+2\sqrt{1570}}{2*10}=\frac{-80+2\sqrt{1570}}{20} $
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