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(F)=(F-7)(F-7)
We move all terms to the left:
(F)-((F-7)(F-7))=0
We multiply parentheses ..
-((+F^2-7F-7F+49))+F=0
We calculate terms in parentheses: -((+F^2-7F-7F+49)), so:We add all the numbers together, and all the variables
(+F^2-7F-7F+49)
We get rid of parentheses
F^2-7F-7F+49
We add all the numbers together, and all the variables
F^2-14F+49
Back to the equation:
-(F^2-14F+49)
F-(F^2-14F+49)=0
We get rid of parentheses
-F^2+F+14F-49=0
We add all the numbers together, and all the variables
-1F^2+15F-49=0
a = -1; b = 15; c = -49;
Δ = b2-4ac
Δ = 152-4·(-1)·(-49)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{29}}{2*-1}=\frac{-15-\sqrt{29}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{29}}{2*-1}=\frac{-15+\sqrt{29}}{-2} $
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